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Lab Report: Genetic Crosses 1
You may wish to construct the Punnett squares on scratch paper first before you fill in the Punnett squares on the Lab Report. Answer the questions below. When you are finished, submit this assignment to your teacher by the due date for full credit.
Part 1: Monohybrid Cross—Predicting Freckles in an F1 Generation
Apply your understanding of how alleles assort and combine during reproduction to evaluate a scenario involving a monohybrid cross.
The allele for having freckles (F) is dominant over the allele for not having freckles (f). Some characteristics in people are inherited as simple dominant and recessive traits. One example is freckles. Freckles is a dominant trait, and the lack of freckles is a recessive trait. In this example, a person with freckles is represented as either FF or Ff, and a person with no freckles is represented as ff.
Total score: Click or tap here to enter text. of 20 points
(Score for Question 1: Click or tap here to enter text. of 2 points)
1. Imagine a mother and a father who both have freckles and are heterozygous for the trait, or Ff. They are the P generation, or parent generation. Create a Punnett square to show their offspring, the F1 generation.
Answer:
Type your answer here.Click or tap here to enter text.
Part 1 Punnett Square

Click or tap here to enter text.
Click or tap here to enter text.

Click or tap here to enter text.
Click or tap here to enter text.

(Score for Question 2: Click or tap here to enter text. of 2 points)
2. Calculate the ratios of the genotypes and phenotypes of the offspring in the F1 generation.
Answer:
Type your answer here.Click or tap here to enter text.
Genotypes:
Phenotypes:
Part 2: Dihybrid Cross—Predicting Flower Color and Seed Shape
Imagine that you are crossing two plants that are heterozygous for flower color and seed shape. The dominant and recessive alleles for these traits are as follows:
purple flowers: P
white flowers: p
round seeds: R
wrinkled seeds: r
(Score for Question 1: Click or tap here to enter text. of 2 points)
1. Determine the genotype of each parent plant and write them below.
Answer:
Type your answer here.Click or tap here to enter text.
Genotype of parent plant 1:
Genotype of parent plant 2:
(Score for Question 2: Click or tap here to enter text. of 4 points)
2. How will the alleles for these traits assort into the gametes that each parent might produce? (Hint: For a reminder on how alleles sort independently into gametes, refer to the illustration in Part 2, Question 2, in the Student Guide.)
Answer:
Type your answer here.Click or tap here to enter text.
Parent plant 1
Gamete 1:
Gamete 2:
Gamete 3:
Gamete 4:
Parent plant 2
Gamete 1:
Gamete 2:
Gamete 3:
Gamete 4:
(Score for Question 3: Click or tap here to enter text. of 4 points)
3. Create a Punnett square to calculate the possible genotypes that can result from a cross between the two parent plants. In a dihybrid cross, the alleles of the gametes of each parent are written along the left side and top of the Punnett square, just as they are for a monohybrid cross. Fill in the squares with the predicted genotypes. Some information has been filled in for you to help you complete a Punnett square for a dihybrid cross.
Answer:
Type your answer here.Click or tap here to enter text.
Part 2 Punnett Square

PPRr
PPRr
ppRR
pprr
(Score for Question 4: Click or tap here to enter text. of 4 points)
4. Look at the Punnett square and list the genotypes that would correspond to each phenotype.
Answer:
Type your answer here.Click or tap here to enter text.
purple flowers, round seeds:
purple flowers, wrinkled seeds:
white flowers, round seeds:
white flowers, wrinkled seeds:
(Score for Question 5: Click or tap here to enter text. of 2 points)
5. Finally, look at the Punnett square again and write the numbers of offspring with each phenotype.
Answer:
Type your answer here.Click or tap here to enter text.
purple flowers, round seeds:
purple flowers, wrinkled seeds:
white flowers, round seeds:
white flowers, wrinkled seeds:

Question

camhdzlopez camhdzlopez

02-12-2021
Biology

contestada

Urgent Help!
Lab Report: Genetic Crosses 1
You may wish to construct the Punnett squares on scratch paper first before you fill in the Punnett squares on the Lab Report. Answer the questions below. When you are finished, submit this assignment to your teacher by the due date for full credit.
Part 1: Monohybrid Cross—Predicting Freckles in an F1 Generation
Apply your understanding of how alleles assort and combine during reproduction to evaluate a scenario involving a monohybrid cross.
The allele for having freckles (F) is dominant over the allele for not having freckles (f). Some characteristics in people are inherited as simple dominant and recessive traits. One example is freckles. Freckles is a dominant trait, and the lack of freckles is a recessive trait. In this example, a person with freckles is represented as either FF or Ff, and a person with no freckles is represented as ff.
Total score: Click or tap here to enter text. of 20 points
(Score for Question 1: Click or tap here to enter text. of 2 points)
1. Imagine a mother and a father who both have freckles and are heterozygous for the trait, or Ff. They are the P generation, or parent generation. Create a Punnett square to show their offspring, the F1 generation.
Answer:
Type your answer here.Click or tap here to enter text.
Part 1 Punnett Square

Click or tap here to enter text.
Click or tap here to enter text.

Click or tap here to enter text.
Click or tap here to enter text.

(Score for Question 2: Click or tap here to enter text. of 2 points)
2. Calculate the ratios of the genotypes and phenotypes of the offspring in the F1 generation.
Answer:
Type your answer here.Click or tap here to enter text.
Genotypes:
Phenotypes:
Part 2: Dihybrid Cross—Predicting Flower Color and Seed Shape
Imagine that you are crossing two plants that are heterozygous for flower color and seed shape. The dominant and recessive alleles for these traits are as follows:
purple flowers: P
white flowers: p
round seeds: R
wrinkled seeds: r
(Score for Question 1: Click or tap here to enter text. of 2 points)
1. Determine the genotype of each parent plant and write them below.
Answer:
Type your answer here.Click or tap here to enter text.
Genotype of parent plant 1:
Genotype of parent plant 2:
(Score for Question 2: Click or tap here to enter text. of 4 points)
2. How will the alleles for these traits assort into the gametes that each parent might produce? (Hint: For a reminder on how alleles sort independently into gametes, refer to the illustration in Part 2, Question 2, in the Student Guide.)
Answer:
Type your answer here.Click or tap here to enter text.
Parent plant 1
Gamete 1:
Gamete 2:
Gamete 3:
Gamete 4:
Parent plant 2
Gamete 1:
Gamete 2:
Gamete 3:
Gamete 4:
(Score for Question 3: Click or tap here to enter text. of 4 points)
3. Create a Punnett square to calculate the possible genotypes that can result from a cross between the two parent plants. In a dihybrid cross, the alleles of the gametes of each parent are written along the left side and top of the Punnett square, just as they are for a monohybrid cross. Fill in the squares with the predicted genotypes. Some information has been filled in for you to help you complete a Punnett square for a dihybrid cross.
Answer:
Type your answer here.Click or tap here to enter text.
Part 2 Punnett Square

PPRr
PPRr
ppRR
pprr
(Score for Question 4: Click or tap here to enter text. of 4 points)
4. Look at the Punnett square and list the genotypes that would correspond to each phenotype.
Answer:
Type your answer here.Click or tap here to enter text.
purple flowers, round seeds:
purple flowers, wrinkled seeds:
white flowers, round seeds:
white flowers, wrinkled seeds:
(Score for Question 5: Click or tap here to enter text. of 2 points)
5. Finally, look at the Punnett square again and write the numbers of offspring with each phenotype.
Answer:
Type your answer here.Click or tap here to enter text.
purple flowers, round seeds:
purple flowers, wrinkled seeds:
white flowers, round seeds:
white flowers, wrinkled seeds:

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marianaegarciaperedo marianaegarciaperedo · Answer 1 · 2021-12-10T13:43:52+01:00

Assuming diallelic genes, that express complete dominance, and assort independently, 1) Genotypic ratio=1:2:1. Phenotypic ratio=3:1 / 2) Parental genotype: PpRr. Gametes= PR, Pr, pR, pr. Phenotypic ratio: 9:3:3:1

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We will assume diallelic genes that express complete dominance. In cases where two or more genes are involved, we will assume they are not linked, and alleles assort independently.

1) FRECKLES

F is the dominant allele that codes for freckles

f is the recessive allele that codes for no-freckles

Cross: Between a mother and a father who both have freckles and are heter0zyg0us for the trait

Parentals) Ff x Ff

Gametes) F f F f

Punnett square) F f

F FF Ff

f Ff ff

F1) Genotype

1/4 = 25% of the progeny is expected to be h0m0zyg0us dominant, FF

2/4 = 1/2 = 50% of the progeny is expected to be heter0zyg0us, Ff

1/4 = 25% of the progeny is expected to be h0m0zyg0us recessive, ff

Phenotype

3/4 = 75% of the progeny is expected to express freckles, FF + Ff

1/4 = 25% of the progeny is expected to not express freckles, ff

Genotypic ratio ⇒ 1:2:1

Phenotypic ratio ⇒ 3:1

2) FLOWER COLOR AND SEED SHAPE

P is the dominant allele that codes for purple flowers

p is the recessive allele that codes for white flowers

R is the dominant allele that codes for round seeds

r is the recessive allele that codes for wrinkled seeds

Cross: Between two plants that are heter0zyg0us for flower color and seed shape

Parentals) PpRr x PpRr

Gametes) PR, Pr, pR, pr PR, Pr, pR, pr

Punnett square) PR Pr pR pr

PR PPRR PPRr PpRR PpRr

Pr PPRr PPrr PpRr Pprr

pR PpRR PpRr ppRR ppRr

pr PpRr Pprr ppRr pprr

F1) Genotype

1/16 individuals are expected to be PPRR

2/16 individuals are expected to be PPRr

1/16 individuals are expected to be PPrr

2/16 individuals are expected to be PpRR

4/16 individuals are expected to be PpRr

2/16 individuals are expected to be Pprr

1/16 individuals are expected to be ppRR

2/16 individuals are expected to be ppRr

1/16 individuals are expected to be pprr

Phenotype

9/16 individuals are expected to have purple flowers with round seeds, PPRR + PpRR + PPRr + PpRr

3/16 individuals are expected to have purple flowers and wrinckled seeds, PPrr + Pprr

3/16 individuals are expected to have white flowers and round seeds, ppRR + ppRr

1/16 individuals are expeceted to have white flowers and wrinckled seeds, pprr.

Phenotypic ratio ⇒ 9:3:3:1

Genotype of parent plant 1: PpRr

Gamete 1: PR
Gamete 2: Pr
Gamete 3: pR
Gamete 4: pr

Genotype of parent plant 2: PpRr

Gamete 1: PR
Gamete 2: Pr
Gamete 3: pR
Gamete 4: pr

PHENOTYPE GENOTYPE

purple flowers, round seeds: PPRR, PpRR, PPRr, PpRr

purple flowers, wrinkled seeds: PPrr, Pprr

white flowers, round seeds: ppRR, ppRr

white flowers, wrinkled seeds: pprr

PHENOTYPE NUMBER

purple flowers, round seeds: 9

purple flowers, wrinkled seeds: 3

white flowers, round seeds: 3

white flowers, wrinkled seeds: 1

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You can learn more about monohybrid and dihybrid crosses at

https://brainly.com/question/1185199?referrer=searchResults

https://brainly.com/question/24076691?referrer=searchResults

https://brainly.com/question/2669862?referrer=searchResults