Question

Solve the following equation..
$\huge \frac{3x}{10} + =6$

Correct answer needed.​

Answer 1

$\underline{ \bf \huge Appropriate \: Question :-}$

$\: \dfrac{3x}{10} = 6$

$\underline{\huge\bf \: R equired \: Solution:-}$

We need to find the value of $\it x$ on the Given equation.

$\underline{\bf \: Multiply \: both \: sides \: by \: 10 :}$

$: \implies \tt \: \dfrac{3x}{10} \times 10 = 6 \times 10$

On cancelling 10 and 10,1 is the result, which equals to 3x/1, that has no value of 1 as the denominator is 1.

$: \implies \tt \dfrac{3x}{ \cancel{10}} \times \cancel{ 10} = 6 \times 10$

On multiplying,60 is the result.

$: \implies \tt \: {3x} = 60$

$\underline{\bf \: Divide \: both \: sides \: by \: 3 : }$

$: \implies \tt \: \dfrac{3x}{3} = \dfrac{60}{3}$

Use cancellation method to cancel 3 and 3,and then cancel 60 and 3, which results to 20.

$: \implies \tt \: {}^{1} \dfrac{ \cancel3x}{ \cancel3} = \dfrac{ \cancel{60}}{ \cancel3} {}^{20}$

$: \implies \tt \: 1x = 20$

$: \implies \tt \: x = 20$

$\qquad \boxed{\boxed{\sf x = 20}}$

Henceforth, the value of x is 20.

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