Question

QUESTION 2

What is the pressure in atm of 0.742 mole of gas at 10.91 L and 291 K?

I

Answer 1

The pressure of this gas in atm is equal to 1.63 atm.

Given the following data:

• Number of moles = 0.742 mole

• Volume = 10.91 Liters

• Temperature = 291 K

• Ideal gas constant, R = 0.0821 Latm/molK

To calculate the pressure of this gas, we would use the ideal gas law equation;

$P=\frac{nRT}{V}$

Where;

• P is the pressure.

• V is the volume.

• n is the number of moles of a gas.

• R is the ideal gas constant.

• T is the temperature.

Substituting the given parameters into the formula, we have;

$P=\frac{0.742 \times 0.0821 \times 291}{10.91} \\\\P = \frac{17.73}{10.91}$

Pressure, P = 1.63 atm.

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