For the reaction, calculate how many moles of the product form when 0.046 mol of O2 completely reacts.
Assume that there is more than enough of the other reactant.
2Ca(s)+O2(g)→2CaO(s)
Express your answer using two significant figures.
The balanced equation tells us that we'll get 2 moles of CaO for every one mole of O2. Since we have 0.046 moles of O2, we'll get 0.023 moles of CaO. (2 sig figs)