Question

need help with pre-cal please

Answer 1

Answer:

• x = n² ± n√(n² + 8)

Step-by-step explanation:

• x ≠ 0, n ≠ 0

• 4/x² + 1/x = 1/(2n²)
• (x + 4)/x² = 1/(2n²)
• 2n²(x + 4) = x²
• x² - 2n²x - 8n² = 0
• D = (-2n²)² - 4(-8n²) = 4n⁴ + 32n² = 4n²(n² + 8)
• x = (2n² ± 2n√(n² + 8))/2
• x = n² ± n√(n² + 8)