Answer:
6, 7, 8
Step-by-step explanation:
Let the smallest integer be x.
The next greater one is x + 1.
The greatest of the three is x + 2.
Now we use the sentence "Twice the greatest of three consecutive integers is 10 more that the smallest integer." to write an equation.
2(x + 2) = x + 10
Solve the equation for x to find the smallest of the integers.
2x + 4 = x + 10
x = 6
The next one is x + 1.
x + 1 = 7
The greatest is x + 2.
x + 2 = 8
Answer: 6, 7, 8
Answer:
6, 7, 8
Step-by-step explanation:
You can set up variables to represent each of these integers.
For example: x, x+1, and x+2. Next find out what x is by using what the question has told you.
Since twice the greatest of three consecutive integers is 10 more than the smallest integer, you can set up this equation: (x) + 10 = 2(x + 2). x represents the smallest integer while x + 2 represents the greatest integer.
Next solve for x using PEMDAS.
1. (x) + 10 = 2(x + 2)
2. x + 10 = 2x + 4
3. 2x - x = 10 - 4
4. x = 6
Now you can find the other integers by adding 1 and 2 to 6.
The correct answers should be 6, 7, 8.
