Question

Refer to the following balanced equation in which ammonia
reacts with nitrogen monoxide to produce nitrogen and
water.
4NH3(g) + 6NO(g) → 5N2(8) + 6H2O(l)
How many moles of NO are required to completely react with
2.45 mol NH3 ?

Answer 1

Answer:  3.68 moles (to 3 sig fig)

Explanation:

4NH₃(g) + 6NO(g) → 5N₂(8) + 6H₂O(l)

The mole ratio of NO to NH₃ based on the balanced equation is 6 to 4 (or 3 to 2 in the simplest form)

Therefore in the reaction, there are ³/₂ more moles of NO than NH₃.

⇒ since moles of NH₃ = 2.45 mol  

   then moles of NO    =   2.45 mol × ³/₂  

                                     =   3.675 mol