The centripetal acceleration of Tom sitting half-way from the edge of the merry-go-round is double of the centripetal acceleration of Sarah sitting at the edge of the merry-go-round.
Let the constant rate of their motion, = v
Let the radius of the merry-go-round = R
The centripetal acceleration of Sarah sitting at the edge of the merry-go-round is calculated as;
[tex]a_c_1 = \frac{V^2}{R}[/tex]
The centripetal acceleration of Tom sitting half-way from the edge of the merry-go-round is calculated as;
[tex]a_c_2 = \frac{V^2}{\frac{1}{2} \times R } \\\\a_c_2 = \frac{2V^2}{R} \\\\a_c_2 = 2(\frac{V^2}{R} )\\\\a_c_2 = a_c_1[/tex]
Thus, the centripetal acceleration of Tom sitting half-way from the edge of the merry-go-round is double of the centripetal acceleration of Sarah sitting at the edge of the merry-go-round.
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