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what is the equation of line that passes through(-6,-3) and is parrelel to the line 5x-3y=9

Respuesta :

Answer:

y+3=5/3(x+6)

Step-by-step explanation:

Since it is parallel to 5x-3y=9, you need to find the slope of that line because then you would find the slope to your line.

5x-3y=9

5x=9+3y

5x-9=3y

y=5/3x-3, and the slope would be 5/3.

Now you can apply point slope form [tex]y-y_{1}=m(x-x_{1} )[/tex] to get an equation.

y+3=5/3(x+6)

Answer: [tex]\frac{5}{3}[/tex]x + 7

Step-by-step explanation:

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