The final pressure in the heated can is 2.51 atm
From the question given above, the following data were obtained:
Initial temperature (T₁) = 25 °C = 25 + 273 = 298 K
Initial pressure (P₁) = 1 atm
Final temperature (T₂) = 475 °C = 475 + 273 = 748 K
Final pressure (P₂) =?
The final pressure can be obtained as illustrated below:
[tex] \frac{P_1}{T_1} = \frac{P_2}{T_2} \\ \\ \frac{1}{298} = \frac{P_2}{748} \\ \\ cross \: multiply \\ \\ 298 \times P_2 = 1 \times 748 \\ \\ divide \: both \: side \: by \: 298 \\ \\ P_2 = \frac{748}{298} \\ \\ P_2 = 2.51 \: atm[/tex]
Therefore, the final pressure in the heated can is 2.51 atm
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