The absolute value function that could represent this situation is:
[tex]|D - 42.67| = 0.002[/tex]
The absolute value function is defined by:
[tex]|x| = x, x \geq 0[/tex]
[tex]|x| = -x, x < 0[/tex]
The diameter should be of 42.67 mm with an allowance of 0.002 mm. Thus, the absolute value of the difference between the diameter and of 42.67 should be of 0.002, that is:
[tex]|D - 42.67| = 0.002[/tex]
A similar problem is given at https://brainly.com/question/24514895