Question

The potential energy stored in the compressed spring of a dart gun, with a spring constant of 32. 50 N/m, is 0. 640 J. Find by how much is the spring is compressed.

Answer 1

The spring in the dart gun is compressed by 0.16 m

From the question given above, the following data were obtained:

Spring constant (K) = 50 N/m

Potential Energy (PE) = 0.640 J

Compression (e) =?

The compression experience by the spring can be obtained as follow:

PE = ½ke²

0.64 = ½ × 50 × e²

0.64 = 25 × e²

Divide both side by 25

e² = 0.64 / 25

Take the square root of both side

e = √(0.64 / 25)

e = 0.16 m

Therefore, the spring is compressed by 0.16 m

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