Answer:
specific heat capacity of the unknown is 629.66 J/kg C
Explanation:
As we know that gold is heated to 72.3 degree C and mixed with water at 24.8 degree C
Now the final temperature of the mixture is 26 degree C
here we can say that heat given by the gold = heat absorbed by the water
So we will have
Q_{in} = Q_{out}Q
in
=Q
out
2.62 s (72.3 - 24.8) = 15.6 (4186) (26 - 24.8)2.62s(72.3−24.8)=15.6(4186)(26−24.8)
so we will have
s = 629.66 J/kg Cs=629.66J/kgC
so specific heat capacity of the unknown is 629.66 J/kg C