The identity of the metal is Magnesium, Mg
Let the unknown metal be M
- Next, we shall determine the number of mole of H₂ produced from the reaction.
Pressure (P) = 1 atm
Temperature (T) = 25 °C = 25 + 273 = 298 K
Volume (V) = 9.51 mL = 9.51 / 1000 = 0.00951 L
Gas constant (R) = 0.0821 atm.L /Kmol
Number of mole (n) =?
PV = nRT
1 × 0.00951 = n × 0.0821 × 298
0.00951 = n × 24.4658
Divide both side by 24.4658
n = 0.00951 / 24.4658
n = 3.89×10¯⁴ mole
- Next, we shall determine the mole of the metal needed to produce 3.89×10¯⁴ mole of H₂.
M + 2HCl —> MCl₂ + H₂
From the balanced equation above,
1 mole of M reacted to produce 1 mole of H₂.
Therefore,
3.89×10¯⁴ mole of M will also react to 3.89×10¯⁴ mole of H₂.
- Finally, we shall determine the identity of the metal, M.
Mass of metal = 9.4 mg = 9.4×10¯³ g
Mole of metal = 3.89×10¯⁴
Molar mass of metal =?
Molar mass = mass / mole
Molar mass of metal = 9.4×10¯³ / 3.89×10¯⁴
Molar mass of metal = 24.2 g/mol
Comparing the molar mass of the metal with those in the periodic table, the identity of the metal is Magnesium, Mg
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