Answer:
first and second photo
speed = distance/time
s = d/t
Segment:
A — 90/30 = 3 m/s
B — 120/60 = 2 m/s
C — 250/50 = 5 m/s
D — 120/40 = 3 m/s
E — 60/20 = 3 m/s
total distance = 90+120+250+120+60 = 640m (meters)
total time = 30+50+60+40+20 = 200 (seconds)
average speed = 640/200 = 3.2 m/s
Third photo:
route
A: travelled east 90 meters
B: travelled north 120 meters
C: travelled east 250 meters
D: travelled north 120 meters
E: travelled west 60 meters
speed for each segment was done in pictures 1 and 2
average speed for whole trip was done in pictures 1 and 2
velocities For route: (im Not completely sure)
A: 3m/s
B: 2m/s
C: 5m/s
D: 3m/s
E: -3m/s
