Answer:
(√14)/4
Step-by-step explanation:
You can "rationalize the denominator" after you take the root, or you can make the denominator a perfect square before you take the root.
[tex]\sqrt{\dfrac{7}{8}}=\dfrac{\sqrt{7}}{2\sqrt{2}}=\dfrac{\sqrt{7}}{2\sqrt{2}}\cdot\dfrac{\sqrt{2}}{\sqrt{2}}=\dfrac{\sqrt{14}}{4}\\\\\sqrt{\dfrac{7}{8}}=\sqrt{\dfrac{7}{8}\cdot\dfrac{2}{2}}=\sqrt{\dfrac{14}{16}}=\dfrac{\sqrt{14}}{4}[/tex]
