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A straight line PQ passing through points (1,-6) and (6, 14). Determine whether a straight line which passing through (-4,-8) and (-1,7) is parallel to PQ. Explain your answer. [3 markah / marks)​

Respuesta :

Answer:

line not parallel to PQ

Step-by-step explanation:

Parallel lines have equal slopes

Calculate slopes m of both lines using slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (P (1, - 6) and (x₂, y₂ ) = Q (6, 14 )

[tex]m_{PQ}[/tex] = [tex]\frac{14-(-6)}{6-1}[/tex] = [tex]\frac{14+6}{5}[/tex] = [tex]\frac{20}{5}[/tex] = 4

Repeat with (x₁, y₁ ) = (- 4, - 8 ) and (x₂, y₂ ) = (- 1, 7 )

m = [tex]\frac{7-(-8)}{-1-(-4)}[/tex] = [tex]\frac{7+8}{-1+4}[/tex] = [tex]\frac{15}{3}[/tex] = 5

Since slopes are not equal then lines are not parallel

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