Question

$\huge\mathrm{Question}$


Can someone give me step by step Explanation for this question ?

That would be of great help ~


Thanks for Answering ~ ​

Answer 1

From the stoichiometry of the reaction, the mass of AgNO3 required is 340 Kg.

• Number of moles of I2 produced in the third step = 254 × 10^3 g/254  g/mol = 1000 moles

• In the first step, 1 mole of AgNO3 produces 1 mole of AgI

In the second step, 2 moles of AgI produces 1 mole of FeI2

In the third step, 2 moles of FeI2 produces 2 moles of I2

• Hence;

In the third step;

1000 moles of I2 is produced by 1000 moles of FeI2

• In the second step;

2 moles of AgI produces 1 mole of FeI2

x moles of AgI produces 1000 moles of FeI2

x = 2 moles × 1000 moles/ 1 mole

x = 2000 moles

• In the first step;

2000 moles of AgI is produced by 2000 moles of AgNO3

Mass of AgNO3 required = 2000 moles of AgNO3  × 170 g/mol = 340 Kg

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