Answer:
[tex]-\frac{7w+4}{2}+w-3[/tex]
Step-by-step explanation:
Is this the correct statement?
[tex]-\frac{1}{2}(7w+4)+\frac{1}{5}(5w-15)[/tex]
If so, here's how. While we're here, you don't actually "solve" an expression, you can only simplify it. Solving it implies solving an equation, and that needs an = sign.
Starting on the left. First, distribute the fraction over the parenthesis:
[tex]-\frac{7w+4}{2}+\frac{1}{5}(5w-15)[/tex]
Then, do the same thing on the right. Distribute the fraction over the parenthesis again:
[tex]-\frac{7w+4}{2}+\frac{5w-15}{5}[/tex]
Here, on the right, 5 and 15 have a common factor of 5. Factor that out:
[tex]-\frac{7w+4}{2}+\frac{5(w-3)}{5}[/tex]
Finally, cancel out the 5s:
[tex]-\frac{7w+4}{2}+\frac{w-3}{1}\\\\-\frac{7w+4}{2}+w-3[/tex]
That's as simplified as it gets.