Question

there are two questions
1. what is the energy associated with electromagnetic radiation of 6.34 x 10^15 hertz

2. What is the frequency of one of the bands of the sodium emission spectrum that has a wavelength of 585 nanometers?

Answer 1

1. The energy associated with an electromagnetic radiation of $6.34 \times 10^{15} \;Hertz$ is equal to $4.2 \times 10^{-18}\;Joules$.

2. The frequency of one of the bands of the sodium emission spectrum is $5.13 \times 10^{14}\;Hertz$

Given the following data:

• Frequency = $6.34 \times 10^{15} \;Hertz$

• Wavelength = 585 nm to m = $5.85 \times 10^{-7}\;meters$

Scientific data:

• Speed of light = $3 \times 10^8\;meters$

• Planck constant = $6.626 \times 10^{-34}\;J.s$

1. To determine the energy associated with an electromagnetic radiation of $6.34 \times 10^{15} \;Hertz$, we would apply Einstein's equation for photon energy:

Mathematically, Einstein's equation for photon energy is given by the formula:

$E =hf$

Where:

• E is the energy.

• h is Planck constant.

• f is photon frequency.

Substituting the given parameters into the formula, we have;

$E = 6.626 \times 10^{-34}\times 6.34 \times 10^{15} \\\\E = 4.2 \times 10^{-18}\;Joules$

2. To determine the frequency of one of the bands of the sodium emission spectrum:

Mathematically, the frequency of a wave is given by the formula:

$Frequency = \frac{Speed}{wavelength} \\\\Frequency = \frac{3 \times 10^8}{5.85 \times 10^{-7}} \\\\Frequency =5.13 \times 10^{14}\;Hertz$

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