Respuesta :

Hello mashiamcphee141!

Let's solve for x in the given question.

[tex]\sf\:\frac { x + 3 } { 2 } + \frac { 2 x } { 7 } = 7\\\sf\:7\left(x+3\right)+2\times 2x=98 \\\sf\:7x+21+2\times 2x=98 \\\sf\:11x+21=98 \\\sf\:11x=98-21 \\\sf\:11x=77 \\\sf\:x=\frac{77}{11} \\\boxed{\sf\:x=7 }[/tex]

Steps :-

  • At first, multiply both sides of the equation by the LCM = 14.
  • Now, simplify the equation using distributive property & other operations.
  • We'll get the value of 'x' as 7.

See the attachment if the working is not clear.

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[tex]\mathfrak{Lucazz}[/tex]

Ver imagen ᴜᴋɪʏᴏ

Given that:

[{(x+3)/2} + (2x/7)] = 7

Take the LCM of 2 and 7 is 14.

⇛[{7(x+3)+2(2x)}/14] = 7

⇛[{7x+21 + 4x}/14] = 7

⇛[{11x+21}/14] = 7/1

Now,

By using cross multiplication method,we get

⇛1(11x+21) = 7(14)

⇛11x + 21 = 58

⇛11x = 58-21

⇛11x = 37

∴ x = 37/11

Hence, the value of x will be 37/11 respectively.

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