Question

PLS HELP THIS IS RLLY HARD FOR ME
The two seventh grade classes at VSH Middle School collected the most box tops for a school
fundraiser, and so they won a $600 prize to share among them. Mr. Thie’s 3
rd period class collected
3,760 box tops and Mr. Thie’s 4th period class collected 2,301. How should they divide the money so
that each class gets the same fraction of the prize money as the fraction of the box tops that they
collected
I'll marry whoever get the best answer ;) (❤´艸｀❤)

Answer 1

All together, the students collected 3,760+2,301+1,855=7,916 box tops.

Mr. Aceves’ class collected 3760/7916 of the box tops.

Mrs. Baca’s class collected 2301/7916 of the box tops.

Mr. Canyon’s class collected 1855/7916 of the box tops.

The amount for Mr. Aceves’ class is 3760/7916×600≈284.99

The amount for Mrs. Baca’s class is 2301/7916×600≈174.41

The amount for Mr. Canyon’s class is 1855/7916×600≈140.60

So $284.99 should go to Mr. Aceves’ class, $174.41 should go to Mrs. Baca’s class, and $140.60 should go to Mr. Canyon’s class.

Answer 2

They didn’t say anything about diving the box tops, it’s a trick question you want to divide the money between the 2 classes so you would do 600/2 and you get 300