Question

A raindrop strikes the ground with a speed of 8.5 m/s. The specific heat of water is 4.19 x 103 J/(kg•°C).
What is the raindrop’s change in temperature after it strikes the ground, in degrees Celsius, assuming all its initial kinetic energy goes into heating it?

Answer 1

Answer:

0.00862 °C

Explanation:

When all Kinetic energy goes Into heating we can write

Q= mc × change in temperature

Q = 1/2 mv^2

1/ 2 mv^2 = mc × change in temperature

cancel out m because its in both sides

1/2 v^2 = c × change in temperature

1/ 2 × 8.5 ×8.5 = 4190 × x

x = 0.00862 °C