Based on the information given, the fraction of horsepower that will be applied to the pump will be 1l28.
From the information given, it can be seen that the motor is rated at 1/8 horsepower and used to drive a pump.
Therefore, the fraction of the horsepower that will be applied to the pump if the motor delivers only 2/7 of its rated horsepower will be:
= 2/7 × 1/8.
= 2/56
= 1/28
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