Question

3. Marilyn hit a golf ball on the ground with her driver. Use

the general function for a projectile to write a function

that shows the height in feet of her golf ball as a function

of time. The ball was hit with an initial vertical velocity of

130 feet per second.

h(t) = -16t2 + 130t


a) How long will Marilyn's ball stay in the air?


b) What was the maximum height of the ball?

Answer 1

It will take the ball 4.0625secs to stay in the air

The maximum height of the ball is 264.0625m

Given the function representing the height reached by the golf expressed as;

h(t) = -16t^2 + 130t

The velocity function is expressed as:

v(t) = -32t + 130

At maximum height, the velocity of the ball will be zero, i.e v(t) = 0

0 = -32t + 130

32t = 130

t = 130/32

t = 4.0625

Hence it will take the ball 4.0625secs to stay in the air

b) Substitute t = 4.0625 into the height function to have:

h(t) = -16t^2 + 130t

h(t) = -16(4.0625)^2 + 130(4.0625)

h(4.0625) = -264.0625 + 528.125

h(t) = 264.0625m

Hence the maximum height of the ball is 264.0625m

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