Question

1. When shot from the barrel of a pellet gun (50.00 cm long), a 5.000 gram pellet moves
from rest to 400.0 m/s. What force does the gun exert on the pellet?

Answer 1

The force the gun exerts on the pellet at the given acceleration is 80 N.

The given parameters;

• mass of the pellet, m = 5 g = 0.005 kg
• length of the gun, d = 50 cm = 5 m
• final velocity of the pellet, v = 400 m/s

The acceleration of the pellet is calculated as follows;

$v^2 = u^2 + 2as\\\\400^2 = 0 + 2(a) (5)\\\\400^2 = 10a\\\\160000 = 10a\\\\16,000 \ m/s^2 = a$

The force the gun exerts on the pellet at the given acceleration is calculated as;

$F = ma\\\\F = 0.005 \times 16,000\\\\F = 80 \ N$

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