Given quardratic polynomial is 3x^2+(2k-5)x-7
On Comparing this with the standard quadratic Polynomial ax^2+bx+c
a = 3
b=2k-5
c = -7
Given zeroes α and -α
sum of the zeroes α +(-α) = -b/a
⇛ α +(-α) = -(2k-5)/3
⇛ 0 = -(2k-5)/3
⇛ 0×3 = -(2k-5)
⇛0 = -(2k-5)
⇛-2K+5 = 0
⇛ -2k = -5
⇛ 2k = 5
⇛ k = 5/2
Answer:- The value of k is 5/2.
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