Respuesta :

Answer:

k = - [tex]\frac{16}{15}[/tex]

Step-by-step explanation:

Since x = - 2 is a zero , then p(- 2) = 0 , that is

2(- 2)² - 3(- 2)(5k + 4) = 0

2(4) + 6(5k + 4) = 0 ← distribute parenthesis

8 + 30k + 24 = 0

30k + 32 = 0 ( subtract 32 from both sides )

30k = - 32 ( divide both sides by 30 )

k = [tex]\frac{-32}{30}[/tex] = - [tex]\frac{16}{15}[/tex]

Given Polynomial P(x) = 2x^2-3x(5k+4)

Zero = -2

We know that

If -2 is zero of the Polynomial then it satisfies the given Polynomial

⇛P(-2) = 0

⇛ 2(-2)^2-3(-2)(5k+4)=0

⇛ 2(4)+6(5k+4) = 0

⇛ 8+30k+24 = 0

⇛ 30k+32 = 0

⇛ 30 k = -32

⇛ k = -32/30

⇛ k = -16/15

Answer:- The value of k = -16/15.

Read more:

Similar Questions

If one zero of the quadratic polynomial x2 - 7x + 5k is -2, then find the value of k...

https://brainly.com/question/23887139?referrer

Write the coefficient of i) x3 in 2x + x2 – 5x3 + x4 ii) x2 in (π/3) x2 + 7x – 3 iii) x in √3 - 2√2x + 4x2 Q3. If p(y) = 4 + 3y – y2 + 5y3, find (i) p(0) ii) p(...

https://brainly.com/question/4131444?referrer

ACCESS MORE