Respuesta :

Quotient:

[tex]\dfrac{9x^2 +68x +35}{x+7}\\\\\\=\dfrac{9x^2 +63x +5x +35}{x+7}\\\\\\=\dfrac{9x(x+7) +5(x+7)}{x+7}\\\\\\=\dfrac{(9x+5)(x+7)}{x+7}\\\\\\=9x+5[/tex]

Remainder:

[tex]f(x) = 9x^2+68x+35[/tex]

By the remainder theorem,

[tex]f(-7) = 9(-7)^2 +68(-7) +35 = 441 - 476+35 = 476 - 476 =0\\\\[/tex]

Which is the remainder when f(x) is divided by (x+7)

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