A user dissolves exactly 1 g of ketamine in 1/4 cup of water.
Given 1 cup = 236.5 mL, the volume of 1/4 cup of water is:
1/4 cup × (236.5 mL/1 cup) = 59.13 mL
1 g of ketamine is dissolved in 59.13 mL of water. The concentration of ketamine, in mg/mL, is:
C = 1000 mg / 59.13 mL = 16.91 mg/mL
The volume of this solution that a 59.0 kg user (body mass) would have to consume to experience a high at 0.600 mg/Kg is:
[tex]59.0 kgBM \times \frac{0.600mgKetamine}{1kgBM} \times \frac{1mL Soluiton}{16.91mgKetamine} = 2.09 mL[/tex]
The volume of this solution that a 59.0 kg user (body mass) would have to consume to become unconscious at 2.00 mg/kg is:
[tex]59.0 kgBM \times \frac{2.00mgKetamine}{1kgBM} \times \frac{1mL Soluiton}{16.91mgKetamine} = 6.98 mL[/tex]
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