Respuesta :

Answer:

[tex]y=\frac{1}{3} x-1.[/tex]

Step-by-step explanation:

if A(9;2), B(-3;-2) then it is possible to make up the required equation according to the form:

[tex]1. \ \frac{x-X_B}{X_A-X_B} =\frac{y-Y_B}{Y_A-Y_B}[/tex]

2. after the substitutuion X(A)=9; X(B)=-3; Y(A)=2 and Y(B)=-2 into the form:

[tex]\frac{x+3}{9+3} =\frac{y+2}{2+2}; \ => \frac{x+3}{12} =\frac{y+2}{4}; \ => \frac{x+3}{3} =y+2.[/tex]

or in slope-interception form:

[tex]y=\frac{1}{3} x-1.[/tex]

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