Question

50 points + brainliest answer questions 7 and 8 with work and all

Answer 1

Answer:

7) m∠BHE = 146°

8) m∠BAC = 25°

Step-by-step explanation:

Question 7:

Given that, $\displaystyle\mathsf{\overline{CD}\:||\:\overline{EF}}$, and that $\displaystyle\mathsf{\overline{AB}}$ is a transveral.

We are also provided with the following measures of the angles: m∠DGH = 2x, and m∠FHB = 5x - 51.

∠DGH and ∠FHB are also corresponding angles, as they have corresponding positions on the same side of the transversal, $\displaystyle\mathsf{\overline{AB}}$. These two angles also have the same measure.  

Solve for x:

In order to find the measure of ∠BHE, we could set up an equality statement on ∠DGH and ∠FHB to solve for the value of x.

m∠DGH = m∠FHB

2x = 5x - 51

Add 51 and subtract 2x from both sides of the equation:

2x -2x + 51  = 5x - 2x - 51 + 51

51 = 3x

Divide both sides by 3:

$\displaystyle\mathsf{\frac{51}{3}\:=\:\frac{3x}{3}}$

x = 17

⇒  m∠DGH = 2x = 2(17) = 34°,

⇒  m∠FHB = 5x - 51 = 5(17) - 51 = 34°.

Since ∠FHB and ∠BHE are supplements (whose sum add up to 180°), we could determine the measure of ∠BHE as follows:

m∠BHE + m∠FHB  = 180°

m∠BHE + 34° = 180°

m∠BHE + 34°- 34° = 180°- 34°

m∠BHE = 146°.

Therefore, the measure of ∠BHE is 146°.

Question 8:

Given that ΔABC with $\displaystyle\mathsf{\overline{AC}}$ extended to D, and that m∠ABC = 63° and m∠BCD = 92°:

The Exterior Angle Theorem states that the measure of an exterior angle of a triangle is equal to the sum of the two nonadjacent interior angles. In other words: ∠BCD = ∠BAC + ∠ABC.  

Before we could apply the Exterior Angle Theorem, we must first find m∠BAC. Since ∠BCD and ∠BCA are supplements:

m∠BCD + m∠BCA = 180°

92° + m∠BCA = 180°

92° - 92°+ m∠BCA = 180° - 92°

m∠BCA = 88°

Solve for m∠BAC:

Now that we have the measure for ∠BCA, we can find m∠BAC by applying the Triangle Sum Theorem where it states that the sum of the interior angles of a triangle is equal to 180°.

m∠BCD + m∠ABC + m∠BAC = 180°

92° + 63° + m∠BAC  = 180°

125° + m∠BAC  = 180°

155° - 155° + m∠BAC  = 180° - 155°

m∠BAC  = 25°

Therefore, the measure of ∠BAC is 25°.