Question

John carries a 5 kg bag horizontally to the checkout line. How much work must he
do to move it 8 m at a constant velocity of 1 m/s to the right?

Answer 1

The work John must do to move the bad horizontally to given distance is 2.5 J.

The given parameters;

• mass of the  bag, m = 5 kg
• distance moved by the bad, d = 8 m
• velocity of bag, v = 1 m/s

The acceleration of the bag at the given distance and velocity is calculated as follows;

$v^2 = u^2 + 2as\\\\1^2 = 0 + 2(a)(8)\\\\1 = 16 a\\\\a = \frac{1}{16} \\\\a = 0.0625 \ m/s^2$

The work done in moving the bag to 8m is calculated as follows;

$W = F \times d\\\\W = ma \times d\\\\W = 5 \times 0.0625 \times 8 \\\\W = 2.5 \ J$

Thus, the work John must do to move the bad horizontally to given distance is 2.5 J.

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