Question

Solve the following problems to determine the empirical formula. Show the complete
factors to calculate number of moles, then the molar ration and finally the empirical formula.
1. Calcium bromide is a compound used in photography and the manufactur of fire extinguishing
materials. Analysis of a 20.00 gram sample of calcium bromide yields 4,02 grams of calcium and
15.95 grams of bromine. Calculate the number of moles of both calcium and bromide, then
determine the mole ratio to write an empirical formula for calcium bromide,

Answer 1

The empirical formula of the compound (calcium bromide) is CaBr₂

From the question given above, the following data were obtained:

Ca = 4.02 g

Br = 15.95 g

Empirical formula =?

Divide by their molar mass to obtain their mole

Ca = 4.02 / 40 = 0.1005 mole

Br = 15.95 / 80 = 0.199 mole

Divide by the smallest to obtain the mole ratio

Ca = 0.1005 / 0.1005 = 1

Br = 0.199 / 0.1005 = 2

Therefore, the empirical formula of calcium bromide is CaBr₂

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