Question

A man is 32 years older than his son ten year ago he was three times as old as his son was then find the present age of each?

Answer 1

x-32=y

x-10=3(y-10)=3y-30

X+20=3y

3x-96=3y

Thus, X+20=3x-96, and 2x=116, X=58

Now, 58–32=y, thus, y=26