Question

Find an equation of the line that passes through the points (-2, 1) and (3, 3). Write your equation in either point-slope form, standard form, or slope-intercept form.

Answer 1

• (-2,1)
• (3,3)

m=3-1/3+2=2/5

Equation of line in point slope. form

$\\ \sf\longmapsto y-y_1=m(x-x_1)$

$\\ \sf\longmapsto y-1=2/5(x-(-2))$

$\\ \sf\longmapsto y-1=2/5(x+2)$

$\\ \sf\longmapsto 5y-5=2x+4$

$\\ \sf\longmapsto 2x-5y+9=0$

Answer 2

Step-by-step explanation:

• (X1, Y1) = (-2, 1)
• (X2, Y2) = (3, 3)

m = (Y2 - Y1)/(X2 - X1) = (3 - 1)/(3 + 2) = 2/5

Soo :

y - Y1 = m(x - X1)

y - 1 = 2/5(x - (-2))

y - 1 = 2/5(x + 2)

5y - 5 = 2x + 4

5y - 5 - 4 - 2x = 0

5y - 9 - 2x = 0

2x - 5y + 9 = 0