Question

A car traveling due north at 60 km/hr increased its velocity to 80 m/s due south in 20 seconds. Draw i) speed against time graph, ii) acceleration against time graph.​

Answer 1

The slope of the graph is acceleration of the car with a value of 3.2 m/s².

The given parameters;

• initial velocity of the car, u = 60 km/hr
• final velocity of the car, v = 80 m/s
• time of motion of the car, t = 20 s

The initial velocity of the car in m/s is calculated as follows;

$60 \ \frac{km}{hr} \times \frac{1 \ hr}{3600 \ s} \times \frac{1000 \ m}{1 \ km} = 16.67 \ m/s$

The acceleration of the car is calculated as follows;

$a = \frac{v- u}{t} \\\\a = \frac{80 - 16.67 }{20} \\\\a = 3.2 \ m/s^2$

The graph of the velocity against time and acceleration against time is in the image uploaded.

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