Question

a series of 1125 consecutive integers has a sum which is a perfect cube find the smallest possible positive sum for this series?
please show your work :)

Answer 1

• The smallest possible sum for the series is 91125

If zero is considered to be positive, the answer is zero (0).

otherwise

562 negative consecutive integers, then 0, then 562 positive consecutive integers has a sum of zero (0).

Moving the start, the smallest integer up 1 adds 1125 to the sum.

1125 = 9 * 125

1125 = 9 * 5³

= 9³ * 5³ is the smallest sum

= 45³

= 91125

Therefore the smallest  possible sum is 91125

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