Question

Five years ago, a father was 3 times as old
as his son, now their combined ages amount
to 110 years. How old are they?

Answer 1

Answer:

Father is 80 years old and the son is 30

Step-by-step explanation:

Let father be x and son be y:

x-5 = 3(y-5)

x = 3y-10 ------ eq1

x+y = 110

x = 110 -y -------- eq2

Now if we combine the 2 equations we get:

3y + y = 110+10

y=30 (sons age)

Substituting in equation 2 we get:

x = 110 - 30

x = 80

Therefore, the fathers age is 80 and the sons age is 30.