Answer:
the balanced equation for the above reaction is as follows;
3NiCl₂ + 2K₃PO₄ ---> Ni₃(PO₄)₂ + 6KCl
stoichiometry of NiCl₂ to K₃PO₄ is 3:2
the number of NiCl₂ moles reacted - 0.0102 mol/L x 0.134 L = 0.00137 mol
according to molar ratio
if 3 mol of NiCl₂ reacts with 2 mol of K₃PO₄
then 0.00137 mol of NiCl₂ reacts with - 2/3 x 0.00137 = 0.000911 mol of K₃PO₄
molarity of given K₃PO₄ solution - 0.205 M
there are 0.205 mol in 1000 mL
therefore volume of 0.000911 mol - 0.000911 mol / 0.205 mol/L = 4.44 mL
volume of K₃PO₄ needed is 4.44 mL
