If the area of a rectangle is 12[tex]b^{7}[/tex]b[tex]b^{4}[/tex] and the width of the rectangle is 4[tex]a^{2}[/tex][tex]b^{2}[/tex] , what is the length of the rectangle?

Respuesta :

[tex]\text{Given that,}\\\\\text{Area} = 12 b^7 b b^4 =12 b^{12}\\\\\text{Width} = 4a^2 b^2\\\\\text{Now,}\\\\\text{Length} \times \text{Width} =\text{Area} \\\\\implies \text{Length} = \dfrac{\text{Area}}{\text{Width}}=\dfrac{12b^{12}}{4a^2 b^2} = \dfrac{3b^{10}}{a^2}[/tex]

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