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refer to attachments for the question



In ∆PQR and ∆MNR
Hence by
Side angle side congruency
[tex]\\ \sf\longmapsto ∆PQR\cong ∆MNR[/tex]
Step-by-step explanation:
PQ ≅ MN ⇒ Given
QR ≅ NR ⇒ Given
R is midpoint of PM ⇒ Given
PR ≅ MR ⇒ Definition of midpoint
ΔPQR ≅ ΔMNR ⇒ SSS postulate