Question

Due Tomorrow: Answer question 18 using steps

Answer 1

$\\ \sf\longmapsto tan51=\dfrac{BC}{AB}$

$\\ \sf\longmapsto 1.23=\dfrac{9}{AB}$

$\\ \sf\longmapsto AB=\dfrac{9}{1.23}$

$\\ \sf\longmapsto AB=7.3\approx 7in$

Now

$\\ \sf\longmapsto AC^2=7^2+9^2$

$\\ \sf\longmapsto AC^2=49+81$

$\\ \sf\longmapsto AC^2=130$

$\\ \sf\longmapsto AC^2\approx 11in$