Question

What is the density of a bowling ball with a mass of 3.0 kg and a volume of 0.0050 m 3 ?

0.002 kg/m 3
0.015 kg/m 3
500 kg/m 3
600 kg/m 3

Answer 1

Answer:

600 kg/m³

Explanation:

Formula to use

d = m/v

[] d is the density

[] m is the mass

[] v is the volume

Solving

[Formula] d = m/v

[Plug-in] d = 3/0.0050

[Divide] d = 600 kg/m³

Answer

0.002 kg/m³

0.015 kg/m³

500 kg/m³

600 kg/m³

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Answer 2

Answer:

$\boxed {\boxed {\sf 600 \ kg/m^3}}$

Explanation:

We are asked to find the density of a bowling ball. The density of an object is its mass per unit volume. It is calculated by dividing the mass by the volume.

$\rho= \frac{m}{v}$

The mass of the bowling ball is 3.0 kilograms and the volume is 0.0050 cubic meters.

• m= 3.0 kg
• v= 0.0050 m³

Substitute the values into the formula.

$\rho= \frac{3.0 \ kg}{0.0050 \ m^3}$

Divide.

$\rho= 600 \ kg/m^3$

The density of the bowling ball is 600 kilograms per cubic meter.