314. Find the area under the graph of f(t) = t/(1+t^2) where t is
between t= 0 and t = x. where a > 0 and a does not equal 1 is
fixed, and evaluate the limit as x → .
Infinity

1. From the first to the second passage I multiplied top and bottom by 2. The bottom one stood outside the integral by linearity, the top got inside to get the derivative of the denominator.

2. Quick y substitution, it's a dy/y which should get integrated as the logarythm of the absolute value. This is a situation where you can skip it since you know that you are dealing with positive values (1 is positive, and 1 plus something squared is even greater than 1 which was positive already).

The area as x diverges also diverges

314. Find the area under the graph of f(t) = t/(1+t^2) where t is between t= 0 and t = x. where a > 0 and a does not equal 1 is fixed, and evaluate the limit as x → . Infinity

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314. Find the area under the graph of f(t) = t/(1+t^2) where t is
between t= 0 and t = x. where a > 0 and a does not equal 1 is
fixed, and evaluate the limit as x → .
Infinity