Answer:
No; no sign change of g(x) in that interval
Step-by-step explanation:
The intermediate value theorem tells you there will be at least one zero between any two points where the function changes sign. The table shows sign changes in the intervals [-2, -1], [0, 1], and [1, 2]. So, the three zeros of the cubic lie in those intervals.
There are no additional zeros to be found, and there are no sign changes of g(x) between x=2 and x=3, so there is no zero in the interval [2, 3].
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Additional comments
We can only answer this with certainty because we have already found the locations of the three real zeros this cubic has. If there were two that were unaccounted for, then the possibility might exist for the graph to make an excursion across the x-axis and back in the interval [2, 3].
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First differences of the table values are ...
-5, +1, +2, -3, 0
Second differences are ...
6, 1, -5, 3
Third differences are ...
-5, -6, +8
This table cannot represent a real cubic function. For evenly-spaced x-values, a cubic polynomial must have constant 3rd differences. If the last two values in the table were -1 and -12, the function would be ...
g(x) = -5/6x^3 +1/2x^2 +7/3x -1
You may want to discuss this question with your teacher.
