Answer:
13. PS ≈ 28.30
14. ∠CDB ≈ 68.74°
Step-by-step explanation:
13 =========================
We'll start from the right, at ∠R. We have the measurement of the angle, the adjacent side, and we need to find the measurement of the opposite side. Use the tan function in this case. (think soh-cah-toa)
[tex]tan(28)=\frac{x}{39} \\x=39tan(28)[/tex]
or x ≈ 20.74
Now we know that QS is about 20.74. From ∠P this time, we have the angle, the opposite side, and we need the hypotenuse. sin function this time.
[tex]sin(76)=\frac{39tan(28)}{y} \\ysin(76)=39tan(28)\\y=\frac{39tan(28)}{sin(76)}\\[/tex]
or y ≈ 28.30
PS ≈ 28.30
14 ======================
Start from ∠A and use tan.
[tex]tan(47)=\frac{x}{18} \\x=18tan(47)[/tex]
x ≈ 19.30
Then from ∠CDB, we'll use inverse cos.
[tex]cos^{-1}(\frac{7}{18tan(47)} )= y[/tex]
y ≈ 68.74°
∠CDB ≈ 68.74°
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I'm pretty highly confident this is correct, but it's been a long time since I've done this and the irrational numbers seem strange. If the rest of the assignment was like that though, it should be fine.