Question

The initial temperature of the mixture was +20 °C. The mixture froze at -1.5 °C.
A total of 165 kJ of internal energy was transferred from the mixture to cool and
freeze it.
specific heat capacity of the mixture = 3500 J/kg °C
specific latent heat of fusion of the mixture = 255 000 J/kg
Calculate the mass of the mixture.
Give your answer to 2 significant figures.
[6
M

Answer 1

Answe16000/3500(-1.5-2-)225000= 1.1

Explanation:

Answer 2

The mass of the mixture will be 2.19 ×10⁻³ kg. The unit of mass is kg and it is a scalar quantity.

What is mass?

Mass is a numerical measure of inertia, which is a basic feature of all matter. It is, in effect, a body of matter's resistance to a change in speed or position caused by the application of a force.

In the International System of Units (SI), the kilogram is the unit of mass.

The given data in the problem is;

The initial temperature of the mixture was, $\rm T_i = 20 ^0 \ C$

The mixture froze at the temperature of, $\rm T_F = -1.5 ^0 \ C$

The internal energy is,$\rm E = \rm 165 \ kJ$

The specific heat capacity of the mixture is,$\rm C = 3500 J/kg ^0C$

The specific latent heat of fusion of the mixture is,$\rm l = 255 000 J/kg$

m is the mass of the mixture,

The latent heat is equal to the heat transfer. Because the net work done is zero.

The formula for the heat transfer is found as;

$\rm Q = mCdt \\\\ m = \frac{Q}{Cdt} \\\\ m = \frac{165 }{3500(20-(-1.5)} \\\\ m = 2.19 \times 10^{-3} \ kg$

Hence the mass of the mixture will be 2.19 ×10⁻³ kg.

To learn more about the mass refer to the link;

https://brainly.com/question/13073862