Question

Brenda wants to move a 30.0 kg table, She applies a force of 420 N. Under these conditions, the table EIN initially moves with an acceleration of 1.80

Answer 1

The friction force acting on the table is equal to 366 Newton.

Given the following data:

• Mass of table = 30.0 kg

• Force = 420 Newton

• Acceleration = 1.80 $m/s^2$

To calculate the friction force acting on the table:

The force of friction acting on the table is given by this mathematical expression:

$Force - Force \;of\; friction = Net \;force$

Substituting the given parameters into the formula, we have;

$420 - F = 1.8 \times 30\\\\420 - F = 54\\\\F = 420-54$

Force of friction, F = 366 Newton

Complete Question:

Brenda wants to move a 30.0 kg table, She applies a force of 420 N. Under these conditions, the table initially moves with an acceleration of 1.80 $m/s^2$. Calculate the friction force on the table

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