Consider LHS
(sinθ/1+cosθ) + (1+cosθ/sinθ) =
= [sinθ(sinθ)+(1+cosθ)+(1+cosθ)]/[(1+cosθ)(sinθ)]
= [sin²θ+(1+cosθ)²]/[(1+cosθ)sinθ]
= [sin²θ+1+cos²θ+2cosθ]/[(1+cosθ)sinθ]
[°.° (a+b)² = a²+2ab+b²]
Here, a = 1, b = cosθ
= [(sin²θ+cos²θ)+1+2cosθ]/[(1+cosθ)sinθ]
= [1+1+2cosθ]/[(1+cosθ)sinθ]
[°.° sin²θ+cos²θ = 1]
= [2+2cosθ]/[1+cosθ)sinθ]
= [2(1+cosθ)]/[(1+cosθ)sinθ]
= 2/(sinθ)
[°.° 2/sinθ = cosecθ]
= 2cosecθ = RHS.
Hence, Proved.
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